23964 (Marin Bancoș)
Să de demonstreze inegalitatea ∑ i = 2 n ( i ! ) 2 i < 2 n 3 + 9 n 2 + 13 n − 24 24 . {\displaystyle \sum _{i=2}^{n}{\sqrt[{i}]{\left(i!\right)^{2}}}<{\frac {2n^{3}+9n^{2}+13n-24}{24}}.}
![{\displaystyle \sum _{i=2}^{n}{\sqrt[{i}]{\left(i!\right)^{2}}}<{\frac {2n^{3}+9n^{2}+13n-24}{24}}.}](https://wikimedia.org/api/rest_v1/media/math/render/svg/1947af93e7b21641df1788f97dea330bafe0ac0a)
