E:5763: Difference between revisions
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Din <math>2\left(x-2,5\right) = \frac{3x}{2}</math> se obține <math>x=2</math>. | Din <math>2\left(x-2,5\right) = \frac{3x}{2}</math> se obține <math>x=2</math>. | ||
Cum <math> y = \frac{x}{3}</math>, se obține <math display="block">E\left(x,y\right) = E\left(x,\frac{x}{3}\right) = 2</math> și <math>\sqrt{xy} = \frac{x}{\sqrt{3}}</math>, deci laturile neparalele și baza mică au lungimea <math> | Cum <math> y = \frac{x}{3}</math>, se obține <math display="block">E\left(x,y\right) = E\left(x,\frac{x}{3}\right) = 2</math> și <math>\sqrt{xy} = \frac{x}{\sqrt{3}}</math>, deci laturile neparalele și baza mică au lungimea <math>2</math>m. | ||
Aria lotului este <math>3\sqrt{3}</math>m. | Aria lotului este <math>3\sqrt{3}</math>m. | ||
Latest revision as of 04:16, 8 December 2024
E:5763 (Tudor Rițiu)
Un lot în formă de trapez isoscel are, în metri, baza mică egală cu valoarea numerică a expresieiFailed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E\left(x,y\right) = \frac{\left(x+y\right)^2 - x-y}{x^2-y^2}:\left[ 1 - \frac{1}{x+y}\right]} pentru a cărei valoare satisface proporția
Soluție:
Avem Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E\left(x,y\right) = \frac{\left(x+y\right)^2 - x-y}{x^2-y^2}:\left[ 1 - \frac{1}{x+y}\right] = \frac{\left(x+y\right)\left(x+y-1\right)}{\left(x+y\right)\left(x-y\right)} \cdot \frac{x+y}{x+y-1},} deci Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E\left(x,y\right) = \frac{x+y}{x-y}. }
Din Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2\left(x-2,5\right) = \frac{3x}{2}} se obține Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=2} .
Cum Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y = \frac{x}{3}} , se obține Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle E\left(x,y\right) = E\left(x,\frac{x}{3}\right) = 2} și Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \sqrt{xy} = \frac{x}{\sqrt{3}}} , deci laturile neparalele și baza mică au lungimea Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2} m.
Aria lotului este Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 3\sqrt{3}} m.