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3466 - Num Sum Div
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==Rezolvare== <syntaxhighlight lang="python" line="1"> #3466 - Num Sum Div def conditii(n, numere): return len(numere) == n and \ 1 <= n <= 10_000 and \ all(nr < 5_000_000_000 for nr in numere) def num_sum_div(numere): deficiente, perfecte, abundente = 0, 0, 0 for nr in numere: # Însumăm toți divizorii ai lui 'nr' suma = sum(divizor for divizor in range(1, nr // 2 + 1) if nr % divizor == 0) # Dacă suma este mai mică decât 'nr' ... if suma < nr: # ... incrementăm numărul de deficiente deficiente += 1 # Dacă suma este egală cu 'nr' ... elif suma == nr: # ... incrementăm numărul de perfecte perfecte += 1 # Dacă suma este mai mare decât 'nr' ... else: # ... incrementăm numărul de abundente abundente += 1 # Afisăm numărul de deficiente, perfecte și abundente în ordinea cerută de enunț print(deficiente, perfecte, abundente) if __name__ == "__main__": n = int(input()) numere = [int(x) for x in input().split()] if not conditii(n, numere): print("Datele de intrare nu corespund restricțiilor impuse.") else: print("Datele de intrare corespund restricțiilor impuse.") num_sum_div(numere) </syntaxhighlight>
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