27020: Difference between revisions

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'''27020 (Gheorghe Szöllösy)'''
'''27020 (Gheorghe Szöllösy)'''


Să se calculeze suma <math> \sum_{k=0}^\left[\frac{n}{2}\right]  \left\dfrac{1}{4^k \cdot (k!)^2(n-2k)!}\right, n \geq 1 </math>
Să se calculeze suma <math> \sum_{k=0}^\left[\frac{n}{2}\right]  \[left\dfrac{1}{4^k \cdot (k!)^2(n-2k)!}\right], n \geq 1 </math>

Revision as of 17:06, 18 October 2023

27020 (Gheorghe Szöllösy)

Să se calculeze suma Failed to parse (syntax error): {\displaystyle \sum_{k=0}^\left[\frac{n}{2}\right] \[left\dfrac{1}{4^k \cdot (k!)^2(n-2k)!}\right], n \geq 1 }