14683: Difference between revisions
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Dacă x > y atunci relația se scrie <math>2^y(2^{x-y} - 1) = 3^y(3^{x-y} - 1)</math>. | Dacă x > y atunci relația se scrie <math>2^y(2^{x-y} - 1) = 3^y(3^{x-y} - 1)</math>. | ||
Avem <math>2^y | Avem <math>2^y < 3^y</math> și <math>2^{x-y} - 1 < 3^{x-y} -1 </math>, de unde <math>2^y(2^{x-y}-1) < 3^y(3^{x-y} - 1)</math>, ceea ce este fals. | ||
Analog se procedează dacă x < y. În concluzie x | Analog se procedează dacă x < y. În concluzie x = y. | ||
Revision as of 11:55, 16 January 2024
14683 (Răzvan Ceuca)
Fie matricele Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A, B \in \mathcal{M}_3(\mathbb{C}),} care verifică simultan condițiile:
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle AB = BA;}
- matricea Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A}
este nilpotentă și matricea Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle B}
este inversabilă.
Arătați că ecuația Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle AX + XA = B} nu are soluții în Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathcal{M}_3(\mathbb{C})} .
Soluție:
Relația din enunț se mai poate scrie Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2^x - 2^y = 3^x - 3^y} . Presupunem că Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x \neq y} ; atunci x < y sau x > y.
Dacă x > y atunci relația se scrie Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2^y(2^{x-y} - 1) = 3^y(3^{x-y} - 1)} .
Avem Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2^y < 3^y} și Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2^{x-y} - 1 < 3^{x-y} -1 } , de unde Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2^y(2^{x-y}-1) < 3^y(3^{x-y} - 1)} , ceea ce este fals.
Analog se procedează dacă x < y. În concluzie x = y.