Gazeta Matematică nr 27020 2015: Difference between revisions

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Pagină nouă: '''27020 (Gheorghe Szöllösy)''' Să se calculeze suma <math> \sum_{k=0}^{\left[\frac{n}{2}\right]} \frac{1}{4^k \cdot (k!)^2 (n-2k)!}, \quad n \geq 1 </math>
 
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'''27020 (Gheorghe Szöllösy)'''
'''27020 (Gheorghe Szöllösy)'''


Să se calculeze suma <math> \sum_{k=0}^{\left[\frac{n}{2}\right]} \frac{1}{4^k \cdot (k!)^2  (n-2k)!}, \quad n \geq 1
Să se calculeze suma <math> \sum_{k=0}^{\left[\frac{n}{2}\right]} \frac{1}{4^k \cdot (k!)^2  (n-2k)!}, \quad n \geq 1.
</math>
</math>

Latest revision as of 17:59, 18 October 2023

27020 (Gheorghe Szöllösy)

Să se calculeze suma