27020: Difference between revisions

Revision as of 17:03, 18 October 2023

27020 (Gheorghe Szöllösy)

Să se calculeze suma $\sum _{k=0}^{\left[{\frac {n}{2}}\right]}\left[{\dfrac {1}{4^{k}\cdot (k!)^{2}(n-2k)!}}\right],n\geq 1$

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	'''27020 (Gheorghe Szöllösy)'''		'''27020 (Gheorghe Szöllösy)'''

	Să se calculeze suma <math> \sum_{k=0}^\left[\frac{n}{2}\right] \left[\dfrac{n}{2}\right] </math>		Să se calculeze suma <math> \sum_{k=0}^\left[\frac{n}{2}\right] \left[\dfrac{1}{4^k \cdot (k!)^2(n-2k)!}\right], n \geq 1 </math>