2015-12-1: Difference between revisions

From Bitnami MediaWiki
No edit summary
Tag: Manual revert
No edit summary
Line 2: Line 2:


<math>Solutie:\ (Robert \ Rogozsan)</math>
<math>Solutie:\ (Robert \ Rogozsan)</math>
Daca <math> \ f(0) \geq 0</math>, cum <math>f</math> e crescătoare, vom avea ca <math>f(t) \geq 0, \forall t \geq 0</math>, deci <math>2tf(t) + \int_{0}^{t} f(x)\, dx \geq 0, \forall t \geq 0</math>. Atunci luam <math>c \in (0,1)</math> arbitrar si concluzia este verificata. Analog pentru <math> \ f(0) \leq 0</math> (luam <math>c</math> din <math>(-1,0)</math>).
Dacă <math> \ f(0) \geq 0</math>, cum <math>f</math> e crescătoare, vom avea <math>f(t) \geq 0, \forall t \geq 0</math>, deci <math>2tf(t) + \int_{0}^{t} f(x)\, dx \geq 0, \forall t \geq 0</math>. Atunci luăm <math>c \in (0,1)</math> arbitrar și concluzia este verificată. Analog pentru <math> \ f(0) \leq 0</math> (luăm <math>c</math> din <math>(-1,0)</math>).


<math>Observatie:</math> In functie de cum e <math>f(0)</math> fata de <math>0</math>, concluzia se verifica pentru <math>orice \ c \in (0,1)</math> (<math>(-1,0)</math>). Nu avem nevoie de faptul ca <math>f</math> e derivabila, nici de <math>f'(0) \neq 0</math>.
<math>Observație:</math> În funcție de cum e <math>f(0)</math> față de <math>0</math>, concluzia se verifică pentru <math>orice \ c \in (0,1)</math> (<math>(-1,0)</math>). Nu avem nevoie de faptul <math>f</math> e derivabilă, nici de <math>f'(0) \neq 0</math>.

Revision as of 14:18, 2 September 2023

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Problema:} Fie Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f:[-1,1]\to \mathbb{R}} o funcție crescătoare, derivabilă pe cu . Să se arate ca exista cel puțin un punct Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c \in (-1,1), c \neq 0} , cu proprietatea că Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2cf(c) + \int_{0}^{c} f(x)\, dx \geq 0} .

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Solutie:\ (Robert \ Rogozsan)} Dacă Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ f(0) \geq 0} , cum Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f} e crescătoare, vom avea că Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(t) \geq 0, \forall t \geq 0} , deci Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 2tf(t) + \int_{0}^{t} f(x)\, dx \geq 0, \forall t \geq 0} . Atunci luăm Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c \in (0,1)} arbitrar și concluzia este verificată. Analog pentru Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ f(0) \leq 0} (luăm Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c} din Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (-1,0)} ).

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Observație:} În funcție de cum e Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(0)} față de Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0} , concluzia se verifică pentru Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle orice \ c \in (0,1)} (Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (-1,0)} ). Nu avem nevoie de faptul că Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f} e derivabilă, nici de Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(0) \neq 0} .