S:E22.136: Difference between revisions

Revision as of 13:01, 5 December 2024

S:E22.136 (Cristina Vijdeluc, Mihai Vijdeluc)

Aflați numerele $n$ , $p$ natuarale neule pentru care $2n^{2}=253\cdot \left(p!+2022\right)$ , unde $p!=1\cdot 2\cdot 3\cdot \ldots \cdot p$ .

Revision as of 13:01, 5 December 2024 view source Andrei.Horvat (talk \| contribs) 516 edits Created page with "'''S:E22.136 (Cristina Vijdeluc, Mihai Vijdeluc)''' '' Aflați numerele <math>n</math>, <math>p</math> natuarale neule pentru care <math>2n^2 = 253 \cdot \left(p! + 2022)</math>, unde <math>p! = 1\cdot 2\cdot 3\cdot \ldots\cdot p</math>."		Revision as of 13:01, 5 December 2024 view source Andrei.Horvat (talk \| contribs) 516 edits No edit summary Newer edit →
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	'''S:E22.136 (Cristina Vijdeluc, Mihai Vijdeluc)'''		'''S:E22.136 (Cristina Vijdeluc, Mihai Vijdeluc)'''

	'' Aflați numerele <math>n</math>, <math>p</math> natuarale neule pentru care <math>2n^2 = 253 \cdot \left(p! + 2022)</math>, unde <math>p! = 1\cdot 2\cdot 3\cdot \ldots\cdot p</math>.		'' Aflați numerele <math>n</math>, <math>p</math> natuarale neule pentru care <math>2n^2 = 253 \cdot \left(p! + 2022\right)</math>, unde <math>p! = 1\cdot 2\cdot 3\cdot \ldots\cdot p</math>.