https://wiki.universitas.ro/index.php?action=history&feed=atom&title=14309
14309 - Revision history
2026-05-01T08:47:36Z
Revision history for this page on the wiki
MediaWiki 1.42.1
https://wiki.universitas.ro/index.php?title=14309&diff=10610&oldid=prev
Andrei.Horvat at 07:33, 19 January 2025
2025-01-19T07:33:00Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 07:33, 19 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l3">Line 3:</td>
<td colspan="2" class="diff-lineno">Line 3:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici decât <math>3</math>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza <math>3</math> a numărului <math>2012</math>. Cum <math display="block">2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici decât <math>3</math>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza <math>3</math> a numărului <math>2012</math>. Cum <math display="block">2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu <ins style="font-weight: bold; text-decoration: none;"> <math></ins>3<ins style="font-weight: bold; text-decoration: none;"></math></ins>, atunci problema nu mai rămâne adevărată; <ins style="font-weight: bold; text-decoration: none;">numărul <math></ins>2012<ins style="font-weight: bold; text-decoration: none;"></math> </ins>se poate scrie ca o suma de puteri ale lui <ins style="font-weight: bold; text-decoration: none;"> <math></ins>3<ins style="font-weight: bold; text-decoration: none;"></math></ins>, dar suma <ins style="font-weight: bold; text-decoration: none;"><math></ins>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7<ins style="font-weight: bold; text-decoration: none;"></math> </ins>nu se mai scrie, sigur, ca sumă de două pătrate.</div></td></tr>
</table>
Andrei.Horvat
https://wiki.universitas.ro/index.php?title=14309&diff=10609&oldid=prev
Andrei.Horvat at 07:31, 19 January 2025
2025-01-19T07:31:41Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 07:31, 19 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l3">Line 3:</td>
<td colspan="2" class="diff-lineno">Line 3:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici decât <math>3</math>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza 3 a <del style="font-weight: bold; text-decoration: none;">lui </del>2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici decât <math>3</math>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza <ins style="font-weight: bold; text-decoration: none;"> <math></ins>3<ins style="font-weight: bold; text-decoration: none;"></math> </ins>a <ins style="font-weight: bold; text-decoration: none;">numărului <math></ins>2012<ins style="font-weight: bold; text-decoration: none;"></math></ins>. Cum <math <ins style="font-weight: bold; text-decoration: none;"> display="block"</ins>>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math <ins style="font-weight: bold; text-decoration: none;">display="block"</ins>>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td></tr>
</table>
Andrei.Horvat
https://wiki.universitas.ro/index.php?title=14309&diff=10608&oldid=prev
Andrei.Horvat at 07:29, 19 January 2025
2025-01-19T07:29:47Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 07:29, 19 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l3">Line 3:</td>
<td colspan="2" class="diff-lineno">Line 3:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici <del style="font-weight: bold; text-decoration: none;">decât3</del>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici <ins style="font-weight: bold; text-decoration: none;">decât <math>3</math></ins>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td></tr>
</table>
Andrei.Horvat
https://wiki.universitas.ro/index.php?title=14309&diff=10607&oldid=prev
Andrei.Horvat at 07:29, 19 January 2025
2025-01-19T07:29:21Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 07:29, 19 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1">Line 1:</td>
<td colspan="2" class="diff-lineno">Line 1:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (Alexandru Vele)'''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (Alexandru Vele)'''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea<del style="font-weight: bold; text-decoration: none;">:</del>''</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea<ins style="font-weight: bold; text-decoration: none;">''<math display="block">2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math>''Arătați că'' <math display="block">a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math>'''Soluție.'</ins>''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;"><math>2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math></del></div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>sunt mai mici <ins style="font-weight: bold; text-decoration: none;">decât3</ins>, atunci <math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math> poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div> </div></td><td colspan="2" class="diff-side-added"></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;">Arătați că <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math></del></div></td><td colspan="2" class="diff-side-added"></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div> </div></td><td colspan="2" class="diff-side-added"></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;">'''Soluție.''' </del></div></td><td colspan="2" class="diff-side-added"></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div> </div></td><td colspan="2" class="diff-side-added"></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math><del style="font-weight: bold; text-decoration: none;">'' </del>sunt mai mici <del style="font-weight: bold; text-decoration: none;">decât 3</del>, atunci <del style="font-weight: bold; text-decoration: none;">''</del><math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math><del style="font-weight: bold; text-decoration: none;">'' </del>poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td><td colspan="2" class="diff-side-added"></td></tr>
</table>
Andrei.Horvat
https://wiki.universitas.ro/index.php?title=14309&diff=10606&oldid=prev
Andrei.Horvat at 07:28, 19 January 2025
2025-01-19T07:28:08Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 07:28, 19 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1">Line 1:</td>
<td colspan="2" class="diff-lineno">Line 1:</td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (<del style="font-weight: bold; text-decoration: none;">Bogdan Pop</del>)'''</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (<ins style="font-weight: bold; text-decoration: none;">Alexandru Vele</ins>)'''</div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea:''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea:''</div></td></tr>
<tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l7">Line 7:</td>
<td colspan="2" class="diff-lineno">Line 7:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Arătați că <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math></div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Arătați că <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math></div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>''<del style="font-weight: bold; text-decoration: none;">Alexandru Vele, Târgu Lăpuș</del>''</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>''<ins style="font-weight: bold; text-decoration: none;">'Soluție.'</ins>'' </div></td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><br></td></tr>
<tr><td class="diff-marker" data-marker="−"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;">''Soluție. </del>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>'' sunt mai mici decât 3, atunci ''<math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math>'' poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>'' sunt mai mici decât 3, atunci ''<math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math>'' poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</div></td></tr>
</table>
Andrei.Horvat
https://wiki.universitas.ro/index.php?title=14309&diff=10600&oldid=prev
Bogdan.Pop at 12:51, 17 January 2025
2025-01-17T12:51:15Z
<p></p>
<table style="background-color: #fff; color: #202122;" data-mw="interface">
<col class="diff-marker" />
<col class="diff-content" />
<col class="diff-marker" />
<col class="diff-content" />
<tr class="diff-title" lang="en">
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">Revision as of 12:51, 17 January 2025</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1">Line 1:</td>
<td colspan="2" class="diff-lineno">Line 1:</td></tr>
<tr><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (Bogdan Pop)'''</div></td><td class="diff-marker"></td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>'''E:14309 (Bogdan Pop)'''</div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">''Determinați numerele naturale'' <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> ''astfel încât să avem egalitatea:''</ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"><math>2012 = a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s.</math></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">Arătați că <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = m^2 + n^2, m,n\in\Nu</math></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">''Alexandru Vele, Târgu Lăpuș''</ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2" class="diff-side-deleted"></td><td class="diff-marker" data-marker="+"></td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">''Soluție. Dacă <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math>'' sunt mai mici decât 3, atunci ''<math>a_1 \cdot3^x + a_2\cdot3^y + a_3\cdot3^z + a_4\cdot3^t + a_5\cdot3^u + a_6\cdot3^r + a_7\cdot3^s</math>'' poate fi privită ca scrierea în baza 3 a lui 2012. Cum <math>2012 = 2\cdot3^0 + 1\cdot3^1 + 1\cdot3^2 + 2\cdot3^3 + 0\cdot3^4 + 2\cdot3^5. + 2\cdot3^6</math> avem <math>a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 = 2 + 1 + 1 + 2 + 0 + 2 + 2 = 10 = 1^2 + 3^2.</math> Dacă cel puțin unul dintre numerele <math>a_1, a_2, a_3, a_4, a_5, a_6, a_7</math> este mai mare sau egal cu 3, atunci problema nu mai rămâne adevărată; 2012 se poate scrie ca o suma de puteri ale lui 3, dar suma a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 nu se mai scrie, sigur, ca sumă de două pătrate.</ins></div></td></tr>
</table>
Bogdan.Pop
https://wiki.universitas.ro/index.php?title=14309&diff=10596&oldid=prev
Bogdan.Pop: Created page with "'''E:14309 (Bogdan Pop)'''"
2025-01-17T11:55:56Z
<p>Created page with "'''E:14309 (Bogdan Pop)'''"</p>
<p><b>New page</b></p><div>'''E:14309 (Bogdan Pop)'''</div>
Bogdan.Pop