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	<id>https://wiki.universitas.ro/index.php?action=history&amp;feed=atom&amp;title=0589_-_Roy-Floyd</id>
	<title>0589 - Roy-Floyd - Revision history</title>
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	<updated>2026-05-02T06:58:47Z</updated>
	<subtitle>Revision history for this page on the wiki</subtitle>
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	<entry>
		<id>https://wiki.universitas.ro/index.php?title=0589_-_Roy-Floyd&amp;diff=9829&amp;oldid=prev</id>
		<title>Oros Ioana Diana: Pagină nouă: = Cerința = Se dă un graf orientat ponderat cu &lt;code&gt;n&lt;/code&gt; noduri și &lt;code&gt;m&lt;/code&gt; arce – în care fiecare arc are asociat un cost, număr natural strict pozitiv. Folosind algoritmul Roy-Floyd, construiți matricea costurilor minime, &lt;code&gt;a[i][j]&lt;/code&gt; fiind costul minim al unui drum de la &lt;code&gt;i&lt;/code&gt; la &lt;code&gt;j&lt;/code&gt;, dacă există un asemenea drum, sau &lt;code&gt;-1&lt;/code&gt; în caz contrar.  = Date de intrare = Fișierul de intrare &lt;code&gt;roy-floydIN.txt&lt;/code&gt; con...</title>
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		<updated>2024-05-18T20:15:58Z</updated>

		<summary type="html">&lt;p&gt;Pagină nouă: = Cerința = Se dă un graf orientat ponderat cu &amp;lt;code&amp;gt;n&amp;lt;/code&amp;gt; noduri și &amp;lt;code&amp;gt;m&amp;lt;/code&amp;gt; arce – în care fiecare arc are asociat un cost, număr natural strict pozitiv. Folosind algoritmul Roy-Floyd, construiți matricea costurilor minime, &amp;lt;code&amp;gt;a[i][j]&amp;lt;/code&amp;gt; fiind costul minim al unui drum de la &amp;lt;code&amp;gt;i&amp;lt;/code&amp;gt; la &amp;lt;code&amp;gt;j&amp;lt;/code&amp;gt;, dacă există un asemenea drum, sau &amp;lt;code&amp;gt;-1&amp;lt;/code&amp;gt; în caz contrar.  = Date de intrare = Fișierul de intrare &amp;lt;code&amp;gt;roy-floydIN.txt&amp;lt;/code&amp;gt; con...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;= Cerința =&lt;br /&gt;
Se dă un graf orientat ponderat cu &amp;lt;code&amp;gt;n&amp;lt;/code&amp;gt; noduri și &amp;lt;code&amp;gt;m&amp;lt;/code&amp;gt; arce – în care fiecare arc are asociat un cost, număr natural strict pozitiv. Folosind algoritmul Roy-Floyd, construiți matricea costurilor minime, &amp;lt;code&amp;gt;a[i][j]&amp;lt;/code&amp;gt; fiind costul minim al unui drum de la &amp;lt;code&amp;gt;i&amp;lt;/code&amp;gt; la &amp;lt;code&amp;gt;j&amp;lt;/code&amp;gt;, dacă există un asemenea drum, sau &amp;lt;code&amp;gt;-1&amp;lt;/code&amp;gt; în caz contrar.&lt;br /&gt;
&lt;br /&gt;
= Date de intrare =&lt;br /&gt;
Fișierul de intrare &amp;lt;code&amp;gt;roy-floydIN.txt&amp;lt;/code&amp;gt; conține pe prima linie numerele &amp;lt;code&amp;gt;n m&amp;lt;/code&amp;gt;, iar următoarele linii câte un triplet &amp;lt;code&amp;gt;i j c&amp;lt;/code&amp;gt;, cu semnificația: există arcul &amp;lt;code&amp;gt;(i j)&amp;lt;/code&amp;gt; și are costul &amp;lt;code&amp;gt;c&amp;lt;/code&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
= Date de ieșire =&lt;br /&gt;
Fișierul de ieșire &amp;lt;code&amp;gt;roy-floydOUT.txt&amp;lt;/code&amp;gt; va conține matricea construită, câte o linie a matricei pe o linie a fișierului, elementele de pe fiecare linie fiind separate prin exact un spațiu.&lt;br /&gt;
&lt;br /&gt;
= Restricții și precizări =&lt;br /&gt;
&lt;br /&gt;
* &amp;lt;code&amp;gt;1 ≤ n ≤ 100&amp;lt;/code&amp;gt;&lt;br /&gt;
* costul unui arc va fi mai mic decât &amp;lt;code&amp;gt;1000&amp;lt;/code&amp;gt;&lt;br /&gt;
* costul unui drum este egal cu suma costurilor arcelor care îl compun&lt;br /&gt;
&lt;br /&gt;
= Exemplu: =&lt;br /&gt;
&amp;lt;code&amp;gt;roy-floydIN.txt&amp;lt;/code&amp;gt;&lt;br /&gt;
 5 6&lt;br /&gt;
 1 3 1&lt;br /&gt;
 2 1 2&lt;br /&gt;
 4 2 1&lt;br /&gt;
 4 3 8&lt;br /&gt;
 5 3 5&lt;br /&gt;
 5 4 2&lt;br /&gt;
&amp;lt;code&amp;gt;roy-floydOUT.txt&amp;lt;/code&amp;gt;&lt;br /&gt;
 0 -1 1 -1 -1 &lt;br /&gt;
 2 0 3 -1 -1 &lt;br /&gt;
 -1 -1 0 -1 -1 &lt;br /&gt;
 3 1 4 0 -1 &lt;br /&gt;
 5 3 5 2 0 &lt;br /&gt;
&lt;br /&gt;
== Rezolvare ==&lt;br /&gt;
&amp;lt;syntaxhighlight lang=&amp;quot;python&amp;quot; line=&amp;quot;1&amp;quot;&amp;gt;&lt;br /&gt;
INFINIT = 1000000000&lt;br /&gt;
&lt;br /&gt;
def verifica_restrictii(n, m, costuri):&lt;br /&gt;
    if not (1 &amp;lt;= n &amp;lt;= 100):&lt;br /&gt;
        return False&lt;br /&gt;
    if any(c &amp;gt;= 1000 for _, _, c in costuri):&lt;br /&gt;
        return False&lt;br /&gt;
    return True&lt;br /&gt;
&lt;br /&gt;
def roy_floyd():&lt;br /&gt;
    try:&lt;br /&gt;
        with open(&amp;quot;roy-floydIN.txt&amp;quot;, &amp;quot;r&amp;quot;) as fin:&lt;br /&gt;
            linie = fin.readline().strip()&lt;br /&gt;
            if not linie:&lt;br /&gt;
                raise ValueError(&amp;quot;Linia de intrare este goala.&amp;quot;)&lt;br /&gt;
            n, m = map(int, linie.split())&lt;br /&gt;
            costuri = [tuple(map(int, fin.readline().split())) for _ in range(m)]&lt;br /&gt;
    except ValueError as e:&lt;br /&gt;
        with open(&amp;quot;roy-floydOUT.txt&amp;quot;, &amp;quot;w&amp;quot;) as fout:&lt;br /&gt;
            fout.write(f&amp;quot;Datele nu corespund restrictiilor impuse: {e}&amp;quot;)&lt;br /&gt;
        return&lt;br /&gt;
&lt;br /&gt;
    if not verifica_restrictii(n, m, costuri):&lt;br /&gt;
        with open(&amp;quot;roy-floydOUT.txt&amp;quot;, &amp;quot;w&amp;quot;) as fout:&lt;br /&gt;
            fout.write(&amp;quot;Datele nu corespund restrictiilor impuse&amp;quot;)&lt;br /&gt;
        return&lt;br /&gt;
&lt;br /&gt;
    a = [[INFINIT] * (n + 1) for _ in range(n + 1)]&lt;br /&gt;
    &lt;br /&gt;
    for i in range(1, n + 1):&lt;br /&gt;
        a[i][i] = 0&lt;br /&gt;
    &lt;br /&gt;
    for i, j, c in costuri:&lt;br /&gt;
        a[i][j] = c&lt;br /&gt;
    &lt;br /&gt;
    for k in range(1, n + 1):&lt;br /&gt;
        for i in range(1, n + 1):&lt;br /&gt;
            for j in range(1, n + 1):&lt;br /&gt;
                if a[i][j] &amp;gt; a[i][k] + a[k][j]:&lt;br /&gt;
                    a[i][j] = a[i][k] + a[k][j]&lt;br /&gt;
    &lt;br /&gt;
    with open(&amp;quot;roy-floydOUT.txt&amp;quot;, &amp;quot;w&amp;quot;) as fout:&lt;br /&gt;
        for i in range(1, n + 1):&lt;br /&gt;
            for j in range(1, n + 1):&lt;br /&gt;
                fout.write(f&amp;quot;{-1 if a[i][j] == INFINIT else a[i][j]} &amp;quot;)&lt;br /&gt;
            fout.write(&amp;quot;\n&amp;quot;)&lt;br /&gt;
&lt;br /&gt;
if __name__ == &amp;quot;__main__&amp;quot;:&lt;br /&gt;
    roy_floyd()&lt;br /&gt;
&lt;br /&gt;
&amp;lt;/syntaxhighlight&amp;gt;&lt;/div&gt;</summary>
		<author><name>Oros Ioana Diana</name></author>
	</entry>
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