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3630 - codred
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== Cerinţa == Se dă '''n''' un număr natural. Să se calculeze suma '''∑nk=1(k!⋅(k2+k+1))'''. == Date de intrare == Programul citește de la tastatură numărul '''n'''. == Date de ieșire == Programul va afișa pe ecran valoarea sumei, modulo '''1.000.000.007'''. == Restricţii şi precizări == * '''1 ⩽ n ⩽ 10.000.000''' == Exemplul 1 == ; Intrare 3 ; Iesire Datele de intrare corespund restrictiilor impuse 95 == Exemplu 2 == ; Intrare 100000000 ; Iesire Datele de intrare nu corespund restrictiilor impuse == Rezolvare == <syntaxhighlight lang="python" line> def factorial(n, mod): fact = 1 for i in range(1, n + 1): fact = (fact * i) % mod return fact def compute_sum(n): mod = 1000000007 suma = 0 for k in range(1, n + 1): term = (factorial(k, mod) * (k*k + k + 1)) % mod suma = (suma + term) % mod return suma def main(): n = int(input()) if n > 10000000: print("Datele de intrare nu corespund restrictiilor impuse") return suma = compute_sum(n) print("Datele de intrare corespund restrictiilor impuse") print(suma) if __name__ == "__main__": main() </syntaxhighlight> == Explicatie == Suma este '''1!⋅3+2!⋅7+3!⋅13=3+14+78=95'''.
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