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2024 - Divizor 112
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== Cerinta == Se dă un şir format din '''n''' numere naturale nenule. Aflaţi cel mai mic număr natural, diferit de 1, care divide un număr maxim de numere din şir. == Date de intrare == Fișierul de intrare '''divizor112in.txt''' conține pe prima linie numărul '''n''', iar pe a doua linie '''n''' numere naturale nenule separate prin spații. == Date de iesire == Fișierul de ieșire '''divizor112out.txt''' va conține pe prima linie cel mai mic număr natural, diferit de 1, care divide un număr maxim de numere din şir. == Restrictii si precizari == *1 ⩽ n ⩽ 100.000 *numerele de pe a doua linie a fișierului de intrare vor fi mai mici decât 1.000.000 == Exemplul 1 == ;divizor112in.txt :5 :1 2 3 4 5 ;divizor112out.txt :Datele introduse corespund restrictiilor impuse :2 == Exemplul 2 == ;divizor112in.txt :-4 :1000001 64 -89 43580 ;divizor112out.txt :Datele introduse nu corespund restrictiilor impuse == Rezolvare == <syntaxhighlight lang="python3" line="1"> def get_prime_factors(num): factors = {} divisor = 2 while num > 1: while num % divisor == 0: num //= divisor factors[divisor] = factors.get(divisor, 0) + 1 divisor += 1 return factors def find_max_divisor(nums): prime_factors_count = {} max_divisor = None max_count = 0 for num in nums: factors = get_prime_factors(num) for factor, count in factors.items(): prime_factors_count[factor] = max(prime_factors_count.get(factor, 0), count) for factor, count in prime_factors_count.items(): if count > max_count: max_count = count max_divisor = factor return max_divisor def verifica_restrictii(input_file, output_file): # Citire date de intrare with open(input_file, "r") as f: n = int(f.readline()) numbers = list(map(int, f.readline().split())) # Apelare funcție de rezolvare result = find_max_divisor(numbers) # Verificare restricții if 1 <= n <= 100000 and all(1 <= num < 1000000 for num in numbers): # Citire rezultat așteptat with open(output_file, "r") as g: result_asteptat = int(g.readline().strip()) # Verificare rezultat if result == result_asteptat: print("Rezultat corect!") else: print("Rezultat incorect!") print("Rezultat așteptat:", result_asteptat) print("Rezultat obținut:", result) else: print("Date de intrare nevalide!") # Citire date de intrare with open("divizor112in.txt", "r") as f: n = int(f.readline()) numbers = list(map(int, f.readline().split())) # Apelare funcție de rezolvare result = find_max_divisor(numbers) # Scriere date de ieșire with open("divizor112out.txt", "w") as g: g.write(str(result) + "\n") # Apelare funcție de verificare verifica_restrictii("divizor112in.txt", "divizor112out.txt") </syntaxhighlight> == Explicatie == 2 divide două numere din şir.
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