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3944 - Turn 1
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= Exemplu 1: = <code>turn_1IN.txt</code> 5 5 1 alb 2 alb 1 roz 2 roz 3 alb <code>turn_1OUT.txt</code> 2 4 1 4 2 3 5 3 1 5 4 === Explicație === Primul turn este format din cuburile: <code>2 (2,alb), 4 (2,roz), 1 (1,alb)</code>. Al doilea turn este format din cuburile: <code>4 (2,roz), 2 (2,alb), 3 (1,roz)</code> etc. == Exemplu 2: == <code>turn_1IN.txt</code> 16 5 1 alb 2 alb 1 roz 2 roz 3 alb <code>turn_1OUT.txt</code> Datele nu corespund restrictiilor impuse == Rezolvare == <syntaxhighlight lang="python3" line="1"> def afisare(b): non_zero_values = [value for value in b if value != 0] fout.write(" ".join(map(str, non_zero_values)) + '\n') def verif(k): if k > 1: if col[b[k]] == col[b[k-1]]: return False if lat[b[k]] > lat[b[k-1]]: return False return True def verifica_restrictii(n, h, lat, col): if not (1 <= n < 15 and 1 <= h <= 50): fout.write("Datele nu corespund restrictiilor impuse\n") return False for i in range(1, n + 1): if not (1 <= lat[i] <= 10 and 1 <= len(col[i]) <= 20 and col[i].islower()): fout.write("Datele nu corespund restrictiilor impuse\n") return False return True def bkt(k, sp): for i in range(1, n+1): if viz[i] == 0: b[k] = i viz[i] = 1 sp += lat[b[k]] if sp <= h and verif(k): if sp == h: afisare(b[:k+1]) else: bkt(k+1, sp) sp -= lat[b[k]] viz[i] = 0 if __name__ == "__main__": with open("turn_1IN.txt", 'r') as fin, open("turn_1OUT.txt", 'w') as fout: n, h = map(int, fin.readline().split()) lat = [0] * 105 b = [0] * 105 sp = 0 viz = [0] * 105 col = [""] * 105 for i in range(1, n+1): line = fin.readline().split() if len(line) < 2: fout.write("Datele nu corespund restrictiilor impuse\n") exit() lat_str, col[i] = line lat[i] = int(lat_str) if not verifica_restrictii(n, h, lat, col): exit() bkt(1, sp) </syntaxhighlight>
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